Two flat conductors are placed with their inner faces separated by 6.0 mm. If the surface charge density on one of the inner faces is 40 pC/m2, what is the magnitude of the electric potential differences between the two conductors?

Explanation:

Relation between electric field and charge density is as follows.

           E =

where,     = charge density

              = permittivity of free space =

So,   = 0

or,    

Now, formula to calculate the potential difference of two conductors is as follows.

It is given that,

           d = 6.0 mm =

Hence, we will calculate the magnitude of the electric potential differences between the two conductors as follows.

                     =      

                     = 0.0271 volts

thus, we can conclude that value of the magnitude of the electric potential differences between the two conductors is 0.0271 volts.

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