Acar starts from rest and accelerates at a constant rate. after the car has gone 50 m it has a speed of 21 m/s. what is the acceleration of the car?
o a. 2.4 m/s2
o b. 4.4 m/s2
o c. 5.5 m/s2
o d. 0.23 m/s2

4.41ms-2

Explanation:

From rest U=0,therefore when given S=50m and V=21m/s then you apply the formula of linear motion which is V^2=U^2+2as

Then substitute for the given values and reach the answer e.g 21^2=(0)^2+2×a×50

441m/s=100ma

a=4.41ms-2

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