Aparallel-plate capacitor has square plates that have edge length equal to 1.20×102cm and are separated by 1.00 mm. it is connected to a battery and is charged to 12.0 v. 1) how much energy is stored in the capacitor? (express your answer to three significant figures.)

Energy stored in the capacitor will be

Explanation:

We have given edge length of capacitor =

So area A = 1.2×1.2 = 1.44

Separation is given as d  1 mm =

We know that capacitance is given by

Voltage is given as V = 12 volt

We know that energy stored is given by

9.18 x 10^-7 J

Explanation:

length of edge, s = 1.2 x 10^2 cm = 1.2 m

Separation between the plates, d = 1 mm = 0.001 m

V = 12 V

1. Formula for the capacitance of parallel plate capacitor is

Where, A be the area of plates

A = side x side = 1.2 x 1.2 = 1.44 m^2

C = 1.275 x 10^-8 F

Energy stored in a capacitor

U = 9.18 x 10^-7 J

trig 15.3 cos