Based on the time measurements in the table, what
can be said about the speed of the car on the lower
track as compared to the higher track?
distance
traveled
(m)
lower track higher track
elapsed time elapsed time
(s)
(s)
how can the reasoning for the above answer be best
explained? on the higher track, the elapsed time is
6.01
4.92
3.36
calculate speeds for each track. how much faster was
the car on the higher track than the lower track?

f is prop to m1xm2 double m1 double force

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft

answer( sicar );