an alien spaceship is 500 m above the ground and moving at a constant
velocity of 150 m/s upwards. how high above the ground is the ship after 5
seconds?

1250 m

Explanation:

This situation is related to vertical movement and can be modelled by the following equation:

Where:

is the height of the alien spaceship at a given time

is the initial height of the alien spaceship (we are told it was already 500 m above the ground)

is the initial velocity of the alien spaceship, that is also constant. This means the velocity is the same during the whole motion and there is no acceleration.

is the time

is the acceleration

Rewritting the equation with the given conditions:

a small object of mass 3.66 g and charge -17.6 µc is suspended motionless above the ground when immersed in a uniform electric field perpendicular to the ground. what are the magnitude and direction of the electric field?

answer; i believe the correct answer is (40,000 j) good luck