Raindrops fall 1.59 x 10^3 m from a cloud to the ground. if they were not slowed by air resistance, how fast would the drops be moving when they struck the ground?

18 seconds

Explanation:

s = Displacement = 1.59×10³ m

a = Acceleration due to gravity = 9.81 m/s²

u = Initial velocity = 0

v = Final velocity

t = Time taken

Equation of motion

Time taken by the raindrop to reach the ground neglecting air resistance is 18 seconds

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s

54 degrees incident angle = reflected angle

angle is from normal turned to line of ray