According to archimedes’ principle, the mass of a floating object equals themass of the fluid displaced by the object. a swimmer is floating ina nearby pool; 95% of her body’s volume is in the water while 5% of herbody’s volume is above water. determine the density of the swimmer’s body. the density of water is does your answer make sense? whyor why not?

950 Kg/m^3

Explanation: We can deduce from the Archimedes principle that there is a relation between the density and the volumes displaced, as follows:

Density*Volume= Mass

So for equilibrium Density of body= Density of water *Vw/Vb

Being Vw/Vb the relation between  the displaced water and the body volume, and given the water density as 1000 Kg/m^3 we got:

Density(B)= 0.95 * 1000 Kg/m^3.

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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