A sample of gas has a volume of 400 liters when its temperature is 20.C and its pressure is 300.mm of Hg. What volume will the gas occupy at STP?

V₂ = 145.35 L

Explanation:

Given data:

Initial volume = 400 L

Initial pressure = 300 mmHg (300/760 =0.39 atm)

Initial temperature = 20 °C (20 +273 = 293 K)

Final temperature = 273 K

Final volume = ?

Final pressure = 1 atm

Solution:

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

P₁V₁/T₁ = P₂V₂/T₂  

V₂ = P₁V₁T₂  /T₁ P₂

V₂ =  0.39 atm × 400 L × 273 K / 293 K × 1 atm

V₂ = 42588 atm.L.K /293 K.atm

V₂ = 145.35 L

every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. therefore, there must be the same number of atoms of each element on each side of a chemical equation.

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