If a silver wire has a resistance of 4.50 ohms at 20.0 degrees celsius, what is the temperature at which it will have 5.00 ohms resistance?

49.24 °C

Explanation:

R₀ = Resistance of the silver wire at 20.0 °C, = 4.50 Ω

T₀ = initial temperature of the silver wire = 20.0 °C

R = Resistance of the silver wire at temperature "T" = 5 Ω

T = Final temperature of silver wire

α = Temperature coefficient of resistance = 0.0038 °C

Using the equation

R = R₀ (1 + α (T - T₀))

Inserting the values

5 = (4.50) (1 + (0.0038) (T - 20))

T = 49.24 °C

multiply 2kg by latent heat of vap

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