If f(x) is continuous on [1,4] and f(10)=3, f(4)=3 and k=15, then which statement(s) would be true regarding a c value in [1,4] where f(c)=15? will reward branliest!

The intermediate value theorem says that, for a function continuous on the closed interval , there is at least one on the open interval such that either or . Basically, if you know the values of the function at the endpoints of some interval, we can only guarantee the function takes on a value between the values at the endpoints.

In this case, we're told is continuous on [1, 4], and . By the IVT, we know there is some in (1, 4) such that . We don't know for sure that takes on a value of 15 in this interval. So the answer is A.

"image"

step-by-step explanation:

in most of these problems, the notation is that the point with a "prime" is the image of the point without. that is, b' is the image of b.

here, there is no dilation or reflection. there is simply translation (with no direction shown). which figure you call the "preimage" and which one you call the "image" is up to you. as a matter of convention, the naming is as described above.