Physics, 21.08.2019 23:30 adrianmelchor146
A0.54 cm high object is placed 8.5 cm in front of a diverging lens whose focal length is -7.5 cm. what is the height of the image?
Answers: 2
 cm 
= height of the object = 0.54 cm 
= distance of the object = 8.5 cm 
= focal length of the diverging lens = - 7.5 cm 
= distance of the image = ?
cm 
= height of the image 
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A0.54 cm high object is placed 8.5 cm in front of a diverging lens whose focal length is -7.5 cm. wh...
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