Block 1, of mass m1 = 2.70 kg , moves along a frictionless air track with speed v1 = 23.0 m/s . it collides with block 2, of mass m2 = 33.0 kg , which was initially at rest. the blocks stick together after the collision. (a) find the magnitude pi of the total initial momentum of the two-block system.
(b) find vf, the magnitude of the final velocity of the two-block system.
(c) what is the change? k=kfinal? kinitial in the two-block system's kinetic energy due to the collision?

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards

the maxium height is 34m/s