Afarsighted person breaks her current eyeglasses and is using an old pair whose refractive power is 1.550 diopters. since these eyeglasses do not completely correct her vision, she must hold her phone 44.0 cm from her eyes in order to read it. she wears the eyeglasses 2.0 cm from her eyes. how far is her near point from her eyes?

An alpha particle with kinetic energy 12.5 mev makes a collision with lead nucleus, but it is not "aimed" at the center of the lead nucleus, and has an initial nonzero angular momentum (with respect to the stationary lead nucleus) of magnitude l = p0 b, where p0 is the magnitude of the initial momentum of the alpha particle and b=1.40×10−12 m. (assume that the lead nucleus remains stationary and that it may be treated as a point charge. the atomic number of lead is 82. the alpha particle is a helium nucleus, with atomic number 2.) what is the distance of closest approach?