A2000 kg car is driving on a flat road around a turn with a 50 meter radius of curvature. when the road is dry, the car can go around the turn at a maximum speed of 20 m/s without slipping. what is the coefficient of friction between the road and the tires? is this the coefficient for static or kinetic friction?

μ =0.8

This is the  coefficient for  kinetic friction

Explanation:

Given that

m = 2000 kg

r= 50 m

v= 20 m/s

When a car moves around a circular arc the it experience a radial force F

F= m v²/r

To avoid the slipping friction force must be equal to F

Friction force Fr= μ m g

Fr= F

μ m g= m v²/r

μ =  v²/rg

By putting the values

   ( take g =10 m/s²)

μ =0.8

This is the  coefficient for  kinetic friction

mass and volume are the answers you are looking for

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2