Aparticle starts from the origin at t = 0 with an initial velocity of 4.8 m/s along the positive x axis. if the acceleration is (-3.2 i^ + 4.6 j^)m/s2, determine (a)the velocity and (b)position of the particle at the moment it reaches its maximum x coordinate.

Part a)

Velocity = 6.9 m/s

Part b)

Position = (3.6 m, 5.175 m)

Explanation:

Initial position of the particle is ORIGIN

also it initial speed is along +X direction given as

now the acceleration is given as

when particle reaches to its maximum x coordinate then its velocity in x direction will become zero

so we will have

Part a)

the velocity of the particle at this moment in Y direction is given as

Part b)

X coordinate of the particle at this time

Y coordinate of the particle at this time

so position is given as (3.6 m, 5.175 m)

real, smaller and upside-down.   so the answer should be b.