Transverse waves on a string have wave speed v=8.00 m/s, amplitude a=0.0700m, and direction, and at t=0 the x-0 end of the wavelength -0.320m. the waves travel in the -x string has its maximum upward displacement. a) find the frequency, period and wave number of these waves b) write a wave function describing the wave c) find the transverse displacement of a particle at x=0.360m at time t=0.150 d) how much time must elapse from the instant in part (c) until the particle at x-0.360 m next has maximum upward displacement?

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

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