Aboy throws a ball straight up in the air with an initial velocity of v+3 mls . the ball reaches a maximum height and starts towards earth. the boy catches the ball at the same height that it left his hand. how long is the ball in the air? 6. a.) =1.01 s b.) t-0.61s c.) 1-2.32s d.) t=1.23h e.) none of the above.

Option (b)

Explanation:

Let the ball takes time t to reach the maximum height. The final velocity at maximum height is zero.

Use I equation of motion, we get

V = u + gt

0 = 3 - 9.8 x t

t = 0.306 s

As the air friction is negligible, so the ball takes same time to reach the hand of boy. Thus the time taken by the ball in air is

T = 2 t = 2 x 0.306 = 0.61 s

search it up!

explanation:

this could be newton#'s law of cooling. the cooling curve is exponential