Calculate the number of moles of oxygen in a 12.5-l tank if the pressure is 25325 kpa and the temperature is 22°c

= 129.06 moles

Explanation:

Using the ideal gas equation;

PV = nRT

Where; P is the pressure, V is the volumes, n is the number of moles, R is the ideal gas constant and T is the temperature.

In this case; V = 12.5 L, P = 25325 kpa or 249.94 atm, T = 22 + 273 = 295 K and R= 0.08206L atm/mol K

n = PV/RT

 = (12.5 × 249.94)/(0.08206 × 295)

 = 129.06 moles

i think the answer is b