Em uma sapateira irei guarda 3 sapatos 2 chinenelos e 5 tenis quantas sao as dispociçoes possiveis desde que os calçados do mesmo tipo fiquem juntos lado alado na sapateira

6

Step-by-step explanation:

Given, In a shoe rack there will be 3 shoes, 2 flip flops and 5 tennis shoes.

To find :  Number of possible arrangements since the shoes of the same type are together side winged in the shoe rack.

For arrangement we use Permutations.

As the shoes of the same type are together , we consider the type of shoes for arrangement.

Total types =3

Number of ways to arrange them = 3!  [By permutation]

= 3 x 2  x 1

= 6

So, the required number of ways = 6.

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation:

answer: plz put a pic in so i can answer it

step-by-step explanation: