What is the electric force acting between two charges of 0.0042 c and −0.0050 c that are 0.0030 m apart?

a. −2.1 1010 n
b. 2.1 1010 n
c. 6.3 107 n
d. −6.3 107 n

A.−2.1 × 10^10 N

Explanation:

Using the formula;

E = k Q1Q2/d²

Where;

E is the electrical force  

k is the constant  

Q1, Q2 are the two charges  and

d is the distance between the two charges

Therefore;

E = (9 x 10^9) × (0.0042) × (-0.0050) / (0.0030)²  

 = -2.1 x 10^10 N

Therefore; electrical force acting between the two charges is -2.1 x 10^10 N.

true is the correct answer

hope i