Acircuit is set up such that it has a current of 8 a. what would be the new current if the resistance was increased by a factor of 2?

4 A

Explanation:

The relationship between current, voltage and resistance in a circuit is given by Ohm's law:

where

V is the voltage

R is the resistance

I is the current

The equation can also be rewritten as

from which we see that the current is inversely proportional to the resistance, R.

In this problem, the initial current is I = 8 A. Then the resistance is doubled:

R ' = 2R

So the new current is

so the current is halved.

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