A2.75 m wire is bent by a magnetic force of 145 n while it is at an 80.0° angle to a 5.40 t magnetic field. in coulombs, how much charge passes through the wire in 20.0 s? answer with three significant digits.

real answer !

Okay so you know that the force on a current is

F = ILB sin(Θ)

I is the current, and it can be written as Q/t

So

F = QLBsin(Θ)/t

Rearrange for Q

Q = Ft/LBsin(Θ)

Q = 198.3 C

whichever one it is, it's definitely not one that you included on the list you provided.

where's the following? you gotta add it to know what the choices are

explanation: