what is the spring constant of a spring that is compressed by 0.250 cm when a force of 35 n is applied?

a. 140n/cm

b.100n/cm

c.200n/cm

d.150n/cm

a. 140 N/cm

Explanation:

The relationship between force applied, spring constant and compression/stretching of a spring is

where

F is the force applied

k is the spring constant

x is the compression/stretching

In this problem, we have:

x = 0.250 m is the compression

F = 35 N is the force applied

Substituting and re-arranging the equation, we find the spring constant:

wvbbvvv

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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