Which vector below goes form (0, 0) to (2, 2)? a. a b. c c. d d. b

D. b

Explanation:

We see that all vectors start from the origin (0,0). We need to find the vector that goes to (2,2). We can notice that the point (2,2) is located in the 1st quadrant: in fact, the x-coordinate of the point is 2, and the y-coordinate is 2 as well. Therefore, the only vector that goes into the 1st quadrant is b, so this is correct choice.

The other vectors goes to:

a: from (0,0) to (-4,2)

c: from (0,0) to (-2,4)

d: from (0,0) to (2,-4)

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .