Study the scenario. a toy car is pushed across the floor with a force of 4 n to the right. there is 1 n of friction acting on the car to the left. what is the net force acting on the car? 0.25 n 5 n 4 n 3 n

The net force acting on the car is 3 N.

(d) is correct option.

Explanation:

Given that,

Force = 4 N to the right

Friction force = 1 N to the left

We need to calculate the net force acting on the car

According to the question,

When a toy car is pushed across the floor with a force then the normal force applied to the right and the frictional force applied to the left on the car.

Then, the net force = normal force - frictional force

Using formula of net force

Hence, The net force acting on the car is 3 N.

answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

according to question, we have said that if the population has twice its initial population, then it becomes

so, time taken to reach this above mentioned population is given by

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.