An archer shoots an arrow horizontally that hits a target 100m away. a bystander times the flight of the arrow at 2.2s. a) what was the initial velocity of the arrow? b) how far did the arrow drop in the vertical direction?

The archer is fired horizontally.

It hits the target which is at 100 m distance.

The horizontal velocity of the archer is always constant for a projectile in this situation.

The total time of flight is given as 2.2 s

Let the initial velocity is u .

Hence the target distance = ut

                 ⇒ 100 m = u×2.2 s

                   ⇒u = 100÷2.2 m/s

                           =45.45 m/s

We are asked to calculate the vertical distance travelled.

The vertical distance travelled is calculated as-

                                       [ s is the distance and a is the acceleration]

                                      [g is te acceleration due to gravity]

                                       [here we have taken only magnitude]

                                             =23.716 m       [ans]

what is the actual question though?