Car accelerates from 10m/s to 25m/s in 6.0s what is its acceleration? how far did it travel in this time? assume constant acceleration

Acceleration = (change in speed) / (time for the change)

Change in speed = (end speed) minus (start speed)

Change in speed = (25 m/s) - (10 m/s) = 15 m/s .

Acceleration = (15 m/s) / (6 sec) =  2.5 m/s² .

Average speed during the acceleration = (1/2) (10 m/s + 25 m/s)

Average speed during the acceleration = (1/2) (35 m/s)

Average speed during the acceleration = 17.5 m/s

Traveling at the average speed of 17.5 m/s for 6 sec,  the car covers (17.5m/s x 6sec) = 105 meters.

The other way to solve it, using the formula:  D = v₀t + (1/2) a T²

Distance = (initial speed)(time) + (1/2)(acceleration)(time²)

Distance = (10 m/s)(6 sec) + (1/2)(2.5 m/s²)(6.0sec)²

Distance = (60 m) + (1/2)(2.5 m/s²)(36 sec²)

Distance = (60 m) + (45 m) = 105 meters    

weather forecasts are done by collecting data about the current state of the atmosphere mainly the temperature, humidity and wind and using meteorology, to determine the atmosphere that evolves over time. the h and l mean the high and low pressure. the red strip is a warm front. the blue strip is a cold front. the blue and red strip is a stationary front. the purple strip is a occluded front.

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