Awave is traveling down a string at 15 m/s. a snapshot of the wave is shown in the figure below. (a) what is the wave's amplitude? cm (b) what is the wave's wavelength? m (c) what is the wave's frequency? hz (d) what is the wave's period? s

(a) Amplitude=1.5 m

Amplitude is the maximum distance from the mean (zero disturbance) position.Here amplitude= 1.5 m

(b) wavelength= 2 m

Wavelength is the length of one complete wave or distance traveled by a wave in a time equal to Time Period. Here wavelength= 2 m

(c) Frequency=7.5 Hz

using equation for wave velocity V= f λ

15= f (2)

f=7.5 Hz

so frequency=7.5 Hz

(d) Time period= 0.133 s

Time period= T= 1/f

T= 1/7.5

T=0.133 s

so time period=0.133 s

i am pretty sure it is c because when people are closer together, they cannot move as freely. picture being in a mostly full elevator, for instance. the people are right next to you, and you can barely move.

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s