Identify the focus directrix and axis of symmetry of 3x =y2

please help no links!!!

Below in bold.

Step-by-step explanation:

y^2 = 3x is a parabola which is symmetrical about the x-axis and opens to the right.

The general form is y^2 = 4ax where the focus is at (a, 0) and directrix is y = -a.

So for the given parabola,  y^2 = 3x:

4a = 3

a = 3/4.

So the focus is (3/4, 0) and directrix is y = -3/4.

Axis of symmetry is  y = 0     (that is the x axis).

it would rotate about 180 degrees.