The graph of y = x4 – 2x2 + 1 is shown. which point is a relative maximum?

Answer with explanation:

Drawing the graph of,

Used the Identity

(a - b)²=a² - 2 a b + b²

To find the Maximum , we will differentiate the function

y'=2×(x²-1)×(2 x)

  y' = 4 x(x²-1)

For maximum or Minimum

y'=0

→4 x(x²-1)=0

→x=0,∧ x²-1=0

→x²=1

→x=1 ∧ x= -1

So, three critical Points are, x=0,1 and -1.

At, x=0,function attains Maximum Value.

→Maximum value of the function ,is 1.

⇒ you can check graphically also.

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation:

stethere all not eveanp-by-step explanation: