The area of triangle abc is a. 60 u^2 b. 65 u^2 c. 130 u^2 d. 150 u^2

I FOUND YOUR COMPLETE QUESTION IN OTHER SOURCES.
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 Using Heron's Formula we can find the area of the triangle.
 A = root (s (s-a) * (s-b) * (s-c))
 s = (a + b + c) / 2
 Where,
 s: semi-perimeter
 a, b, c: sides of the triangle
 Substituting values:
 s = (15 + 16 + 20) / 2
 s = 25.5
 s = 26
 The area will be:
 A = root (26 * (26-15) * (26-16) * (26-20))
 A = 130.9961832
 A = 130 u ^ 2
 
 The area of triangle ABC is:
 C.
 130 u ^ 2