Shenelle has 100100100 meters of fencing to build a rectangular garden. the garden's area (in square meters) as a function of the garden's width www (in meters) is modeled by: a(w)=-(w-25)^2+625a(w)=−(w−25) 2 +625a, left parenthesis, w, right parenthesis, equals, minus, left parenthesis, w, minus, 25, right parenthesis, start superscript, 2, end superscript, plus, 625 what is the maximum area possible?

625 sq. m.

Step-by-step explanation:

The graden's area is given as :  

For maximization of area,we need to put first order derivative of given equation equals to 0 i.e. a'(w) should be equal to zero.  

On Simplifying :

w = 25 meters

Since we are given that Shenelle has 100 meters of fencing to build a rectangular garden

This means perimeter is equal to 100.

Formula of perimeter of rectangle :

Where l is length

w is width

Plugging w as 25

Dividing 2 in both sides

So, for the maximum area the length should be 25 m and width should 25 m

So, So, maximum area

Hence the maximum possible area is 625 sq. m.

3 1/3 x 2 3/5 = 8 2/3

step-by-step explanation:

just multiply the first number by the second number to get your answer.

(a) common ratio in the given sequence is, 3

(b) push ups will do kendall do on the 20th week

step-by-step explanation:

geometric sequence is a sequence of numbers that follows a pattern were the next term is found by multiplying by a constant called the common ratio(r)

(a)

given the sequence: 6 , 18 , 54 , 162 ,

this sequence is geometric sequence where each term is 3 times the previous term.

therefore,

common ratio(r) = 3.

(b)

a formula for nth term of geometric sequence is given by;

,   where r is the common ratio between the successive terms and is the first term,

to find how many push ups will kendall do on the 20th week.

here. n = 20th term.

in the given sequence first term

then;

simplify:

therefore, push ups will do kendall do on the 20th week