Triangle abc has vertices a(−4, 3) , b(2, 3) , and c(−5, 1) . a dilation with a scale factor of 5 and center at the origin is applied to this triangle. what are the coordinates of c′ c′ in the dilated image? enter your answer in the boxes. c′ has a coordinate pair of

The vertices of the triangle is given by:
A(-4,3), B(2,3), C(-5,1) after the dilation of scale factor 5, the  image of the triangle will be:
A'=5(-4,3)=(-20,15)
B'=5(2,3)=(10,15)
C'=5(-5,1)=(-25,5)
Hence the coordinates of the triangle will be simplified as:
A'(-20,15), B'(10,15), C'(-25,5)

Just tell koda to adjust the number of shapes himself.