Iwill give brainliest for correct answer
a plane is located at c on the diagram. there are two towers located at a and b. the distance between the towers is 7,600 feet, and the angles of elevation are given.
explain your answer
a. find bc, the distance from tower 2 to the plane, to the nearest foot.
b. find cd, the height of the plane from the ground, to the nearest foot.

Part A) Find BC, the distance from Tower 2 to the plane, to the nearest foot.

in the triangle ACD
sin16=CD/(7600+BD)> CD=sin16*(7600+BD)> equation 1 

in the triangle BCD
sin24=CD/BD> CD=sin24*BD> equation 2
equation 1=equation 2
sin16*(7600+BD)=sin24*BD> sin16*7600+sin16*BD=sin24*BD
sin24*BD-sin16*BD=sin16*7600> BD=[sin16*7600]/[sin24-sin16]
BD=15979 ft

in the triangle BCD
cos24=BD/BC> BC=BD/cos24> 15979/cos24> 17491
BC=17491 ft

the answer part 1) BC is 17491 ft

Part 2) Find CD, the height of the plane from the ground, to the nearest foot.

CD=sin24*BD        ( remember equation 2)
BD=15979 ft
CD=sin24*15979 > CD=6499 ft

the answer part 2)  CD is 6499 ft