Arectangular park, with dimensions of 1500 feet by 2000 feet, has a diagonal walking path that goes from the top northeast corner to the bottom southwest corner. how long is the walking path? a) 250 feet b) 2500 feet c) 3500 feet d) 5,000 feet

The length of diagonal is 2500 feet.

Step-by-step explanation:

Given a rectangular park, with dimensions of 1500 feet by 2000 feet, has a diagonal walking path that goes from the top northeast corner to the bottom southwest corner.

we have to find the length of walking path i.e of diagonal.

As all angles of rectangle are of 90° and we have to find the length of diagonal.

∴ By Pythagoras theorem

Hence, the length of diagonal is 2500 feet.

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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