Anybody trying to me on my trig work? ? a helicopter flies horizontally at 100 km/h. an observer notices that it takes 20 seconds for the helicopter to fly overhead to being at an angle of 60. how high above the ground is the helicopter

First convert km/hr to m/sec.
100 km/hr = 100 x 1000 x 1/3600 =27.8 m/sec
Distance covered by helicopter in 20 sec:
s=vt, Where s is the distance, v is the speed and t is the time.
Put values
s=27.8 x 20
s=556 meters
Now to find the height, we use tangent ratio.
Let the height=h
tan ∅= Opposite/ Adjacent
Put values
tan60= h/556
Multiply both sides by 556.
556 x tan 60 = h
or
h= 556 x tan 60
h= 963 meters
The helicopter is 963 feet above the ground.

963 ft

I’d say d hope it