Which theorem or postulate proves that △abc and △def are similar?

select from the drop-down menu to correctly complete the statement.

the two triangles are similar by the

SSS Similarity Theorem

Step-by-step explanation:

The answer is SSS Similarity Theorem because there is no angles labeled.

Hope this helps! ;)

From the given figure:

In triangle ABC

Side AB = 3 units, Side BC = 7 units and Side AC = 6 units.

In triangle DEF

Side DE = 18 units, Side EF = 42 units and Side DF = 36 units.

In triangle ABC and triangle DEF

⇒

SSS(Side-Side-Side) similarity theorem states that if three sides in one triangle are in same proportion to the corresponding sides of the other triangle, then these two triangles are similar

then, by SSS similarity theorem;

ΔABC ΔDEF

Therefore, the given two triangles are similar by SSS similarity theorem

see below

step-by-step explanation:

7.   there are 10 data points in the set.   the middle point is between 5 and 6.   the middle point in the top half is 8   and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term   point 8 = 100   point 3 = 88

iqr = 100-88 = 12

final   point 8 = 93   point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6.   b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical .   there is an outlier for the males that skews the data

5.   the   iqr is a better measure of spread for the movies and basketball games.   since the basketball game has an outlier, we do not want to use standard deviation for measurement.  

3.   the exam median is much higher than the class median.   the median line is farther to the right on the exams

2.   there is no way to tell what the means are from the box and whisker plots.