Find the net charge of a system consisting of 6.16×106 electrons and 7.68×106 protons. Express your answer using three significant figures. Qnet = 2.43×10−13 C

2.43 * 10^(-13) C

Explanation:

The net charge of the system is given as the sum of the total charge of the electrons and the charge of the protons.

Qnet = (Ne * Qe) + (Np * Qp)

Ne = number of electrons = 6.16 * 10^6

Np = number of protons = 7.68 * 10^6

Charge of an electron = -1.602 * 10^(-19) C

Charge of a proton = 1.602 * 10^(-19) C

Qnet = (6.16 * 10^6 * -1.602 * 10^(-19)) + (7.68 * 10^6 * 1.602 * 10^(-19))

Qnet = -9.87 * 10^(-13) + 12.30 * 10^(-13)

Qnet = 2.43 * 10^(-13) C

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when jerome paddle in flowing river towards east the net speed of jerome will increase

so the net speed of jerome will be given as

now the speed of paul will be same as it is given as he is running on the ground

so

so here we can say since the speed of jerome is more so he will win the race

now as we know the distance so the time difference is given as

so jerome will reach first and the time difference will be 203.55 s or 3.4 min