5write a recursive method that returns the number of 1's in the binary representation of n. use the fact that this is equal to the number of 1's in the representation of n/2, plus 1, if n is odd.

Assuming n is a decimal number.
Divide n by 2 repeatedly, and summing the remainders will give the number of one's in binary representation.

pseudocode of algorithm:
Enter value of n:
sum=0;
while n>0 {
    sum=mod(n,2);
    n=n/2   [integer division]
}
Display n, sum

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