If the equation below is solved by graphing, which statement is true? log(6x+10)=log1/2x the curves intersect at approximately x = 0.46. the curves intersect at approximately x = 0.75. the curves intersect at approximately x = 1.11. the curves intersect at approximately x = 3.07.

Option A -The curves intersect at approximately x = 0.46.

Step-by-step explanation:

Given : The equation

To find : Which statement is true about the equation.

Solution :

Let the first equation

Let the second equation  

The equation and are equal

which means the curve intersect at some point.

First we plot the graph of the equations.

The graph is attached below.

The intersection point of the equation is (0.464,1.107)

The curves intersect at approximately x = 0.46.

Therefore,Option A is correct.

Verification :

The curve intersect at approximately x=0.46

Step-by-step explanation:

Given equation

Here we have both sides log function.

We will draw the graph of left and right side separately using graph.

Left side

Using graphing calculator we draw both graph on same coordinate place.

Please see the attachment for graph.

As we can see in the graph y1 and y2 intersect at point (0.46,1.12)

Thus, The curve intersect at approximately x=0.46

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180