What is the equation of a line that passes through the point (1, 8) and is perpendicular to the line whose equation is y=x/2+3 ?

Y = x/2 + 3x/2 is the same as 1/2xso u have a slope of 1/2.
A perpendicular line will have a negative reciprocal slope. To find the negative reciprocal, flip the slope and change the sign. So we have 1/2and we flip it making it 2/1and we change the sign making it -2/1 or just -2. So ur perpendicular line will have a slope of -2.

y = mx + b
slope(m) = -2
(1,8)...x = 1 and y = 8
now we sub and find b, the y int
8 = -2(1) + b
8 = -2 + b
8 + 2 = b
10 = b
so ur perpendicular equation is : y = -2x + 10 <==

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