What is the density (In g/L) of a gas with a molar mass of 2.016 g/mol at 4.77 atm and 118k?

0.99g/L

Explanation:

Let us obtain an express for the density based on the data given from the question. This is illustrated below:

PV = nRT

V = nRT/P (1)

But: n = Mass(m) /Molar Mass (M) i.e n = m/M.

Substituting the value of n into equation 1, we have:

V = nRT/P

V = mRT/MP

Now, divide both side by m

V/m = RT/MP

Now, let us invert the above equation:

m/V = MP /RT. (2)

But: Density = m/V

Replacing m/V with Density in equation 2, we have :

Density = MP /RT

Data obtained from the question:

Molar Mass (M) = 2.016 g/mol

P = 4.77 atm

T = 118k

R = 0.082atm.L/mol.K

Density = MP /RT

Density = (2.016 x 4.77) /(0.082x118)

Density = 0.99g/L

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