What is the factored form of 125a^6-64

Step-by-step explanation:

WE can write 125 as 5^3

Also a^6 = (a^2)^3

64  can be written as 4^3

Now we apply a^3 - b^3 formula

a= 5a^2  and b = 4

Plug in the values in the formula

WE factored it completely

step-by-step explanation :

we know that

the measurement of the outer angle is the semi-difference of the arcs which comprises

in this problem

m< xzy is the outer angle

substitute the values

the measure of angle xoy is equal to

> by central angle

substitute the value

the terms of a geometric sequence can be found by beginning with the first term and multiplying by the common ratio repeatedly. a recursive formula for a geometric sequence with common ratio r is given by an=ran−1 a n = r a n − 1 for n≥2 n ≥ 2 .

step-by-step explanation: