What is the equation of the line that passes through (-3, -1) and has a slope of 2/5 ? put your answer in slope-intercept form. a y= 2/5x+1/5 b y=2/5x-1/5 c y=-2/5x-1/5

  a.  y = 2/5x + 1/5

Step-by-step explanation:

In point-slope form, the equation of a line with slope m through point (h, k) can be written

  y = m(x -h) +k

Then a line with slope 2/5 through the point (-3, -1) will have point-slope equation ...

  y = (2/5)(x +3) -1

This can be simplified to the desired form:

  y = 2/5x +6/5 -1 . . . . . . eliminate parentheses; next, collect terms

  y = 2/5x + 1/5

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

options a,b,c are the right answer.

step-by-step explanation:

a linear parent function is always represented as y = x

if we write this function in the form of y=mx+c

⇒

or  

now if we plot a graph we will find these characteristics:

1) y intercept of the graph is zero so its a straight line passing through origin.

2) as we can see in both the forms of function written, values of x and y may be either positive or negative for the positive slope means points on the graph are either in first quadrant or in third one.

3) it's slope is one.