The length of a rectangle is 2 more than the width and the perimeter is 80. find the dimensions of the rectangle

Let width = x  then
2x+ 2(x + 2) = 80
4x + 4 = 80
4x = 76
x = 19  

so the width is 19 and the length is 21 answer

Let L represent the length of the rectangle
let W represent the width of the rectangle
the length is 2 more than the width
L = 2 + W
Let the Perimeter = P
P = 2(L + W)
substitute L = 2 + W, and P =80 in the Formula above
80 = 2( 2 + W + W)
80 = 2(2 + 2W)
80 = 4 + 4W
4W = 80 - 4
4W = 76
W = 19
L = 2 + W
L = 2 + 19
L = 21
the width is 19
the length is 21
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