Asap given the system of linear equations. x=y+3 y=-4x-3 part a: solve the linear system of equations by graphing part b: use substitution to solve the linear system of equations part c: use addition to solve the linear system of equations in your final answer, include all of your work, the graph of the equations and the solution.

A) I included a graph, look below.

B)

Input the y in x = y + 3.

x = (-4x - 3) + 3
x = -4x + 0
Add 4x to both sides.
5x = 0
Divide both sides by 5.
x = 0

Input that x value in y = -4x - 3

y = -4(0) - 3
y = 0 - 3
y = -3

(0, -3)

C)

Convert both equations to Standard Form.

x = y + 3
Subtract y from both sides.
x - y = 3

y = -4x - 3
Add 4x to both sides.
4x + y = -3

Add the equations together.

4x + y = -3
x - y = 3
equals
5x = 0
Divide both sides by 5.
x = 0

Input that into one of the original equations.

0 = y + 3
Subtract 3 from both sides.
-3 = y

(0, -3)

2x + 3y = 114x + 2y = - 2 ( original equation x -1)4x + 6y = 22 ( original equation x 2)- 4x + 2y = - 2= 4y = 24÷4y = 62x + 18 = 11-182x = - 7÷2x = - 3.5