12 yellow balls and 9 red balls are placed in an urn. two balls are then drawn in succession without replacement. what is the probability that the first ball drawn is a red ball if the second ball drawn is yellow? a) 0.8333 b) 0.4500 c) 0.5714 d) 0.4762 e) 0.2593 f) none of the abov

If 21 balls are placed in an urn, 12 being yellow, and 9 being red, the probability that the first ball drawn is a red ball is always 9/21 or approximately 0.4286. This answer is true regardless of what color the second ball is. The answer to this question is f) None of the above.

1. isolate the variable, in this case, d. subtract 35.5 on both sides of the equation.2. 52 subtracted by 35.5 is 16.53. therefore your answer would be d= 16.5this is the basics of pre algebra, isolating variable through adding, subtracting, multiplying, and dividing, if you have any other questions to ask just comment!