Which number is divisible by 3 and 5
a. 130
b. 325
c. 4113
d. 2040

A number that is divisible by 5 is one that ends with either a 5 or 0.  To find a number that is divisible by 3 add up the digits and if they are divisible by 3, the number also is.  That rules c out because it doesn't end with a 5 or 0.  130 and 325 won't work because they are not divisible by 3.  The answer would be 2040.

i = 2 / - 5

step-by-step explanation:

evaluation of ( 2 - 4 ) ( p + q ) when p = 2 and q = 5 i, by putting values of p and q,                                                                    

0 = ( 2 - 4 ) ( p + q )0 = ( 2 - 4 ) ( 2 + 5 i ),   by multiplying these0 = ( 4 + 10 i - 8 - 20 i )0 = 4 - 8 + 10 i - 20 i0 = - 4 -10 i   0 = 2 ( - 2 - 5 i )0 / 2 = - 2 - 5 i- 2 - 5 i = 0- 5 i = 2i = 2 / - 5