Answers: 1
![\sqrt[]{12}=\sqrt[]{2^2\cdot3}=\text{2}\sqrt[]{3}](/tpl/images/2898/0189/974d4.png)
![\begin{gathered} 3\cdot(2\sqrt[]{3})+8\cdot(2\sqrt[]{3})-\sqrt[]{6} \\ 6\sqrt[]{3}+16\sqrt[]{3}-\sqrt[]{6} \\ 22\sqrt[]{3}-\sqrt[]{6} \end{gathered}](/tpl/images/2898/0189/8d8cf.png)
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