I need the answers to these problems for my test corrections.

1.   y = 12

    x = 7.9

2.  AB = 5

    AC = 5√3

Step-by-step explanation:

1. If you call the straight up line of both triangles is z, then

(9 + 7)^2 = y^2 + z^2

=> z^2 = 256 - y^2

x^2 + 7^2 = z^2

=> z^2 = x^2 + 49

so 256 - y^2 = x^2 + 49

x^2 = 207 - y^2

for the left smaller triangle: 9^2 + x^2 = y^2

y^2 = x^2 + 81

Substitute:

y^2 = (207 - y^2) + 81

2y^2 = 288

y^2 = 144

y = 12

x^2 = 207 - y^2 = 207 - 144 = 63

x = 7.9

2. Sin(30) = AB/BC

=> AB = BC x sin(30) = 10 x 0.5 = 5

Cos(30) = AC/BC

=> AC = BC x cos(30) = 10 x √3/2 = 5√3

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source

1^3 + 2^3 + 3^3 +4^3 = (1+2+3+4)^2

step-by-step explanation:

i am only able to answer the first part. i am not sure about the second part. sorry